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A bookstore stocks of its books as fiction works, and less t
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24 Feb 2020, 05:40
24 Feb 2020, 05:40
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64% (01:13) correct
36% (02:14) wrong based on 25 sessions
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A bookstore stocks of its books \(\frac{1}{5}\) as fiction works, and \(\frac{1}{3}\) less than the fiction books as self-help books. What fraction of the total books are the fiction and self-help books?
A. \(\frac{3}{5}\)
B. \(\frac{11}{30}\)
C. \(\frac{4}{15}\)
D. \(\frac{2}{15}\)
E. \(\frac{1}{3}\)
Kudos for the right answer and explanation[/m]
A. \(\frac{3}{5}\)
B. \(\frac{11}{30}\)
C. \(\frac{4}{15}\)
D. \(\frac{2}{15}\)
E. \(\frac{1}{3}\)
Kudos for the right answer and explanation[/m]
Re: A bookstore stocks of its books as fiction works, and less t
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12 May 2020, 10:10
12 May 2020, 10:10
2
Let total books be x.
number of fiction books = x/5
self-help books are 1/3 less than the fiction books,
=> number of self-help books = x/5 - (1/3)*(x/5) = (2/3)*(x/5)
so, their sum is = x/5 + (2/3)*(x/5)
= (x/5)*[1 +(2/3)]
= (x/5)*(5/3)
= x/3
number of fiction books = x/5
self-help books are 1/3 less than the fiction books,
=> number of self-help books = x/5 - (1/3)*(x/5) = (2/3)*(x/5)
so, their sum is = x/5 + (2/3)*(x/5)
= (x/5)*[1 +(2/3)]
= (x/5)*(5/3)
= x/3
Re: A bookstore stocks of its books as fiction works, and less t
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29 Aug 2021, 05:46
29 Aug 2021, 05:46
rishabhrbs96 wrote:
Let total books be x.
number of fiction books = x/5
self-help books are 1/3 less than the fiction books,
=> number of self-help books = x/5 - (1/3)*(x/5) = (2/3)*(x/5)
so, their sum is = x/5 + (2/3)*(x/5)
= (x/5)*[1 +(2/3)]
= (x/5)*(5/3)
= x/3
number of fiction books = x/5
self-help books are 1/3 less than the fiction books,
=> number of self-help books = x/5 - (1/3)*(x/5) = (2/3)*(x/5)
so, their sum is = x/5 + (2/3)*(x/5)
= (x/5)*[1 +(2/3)]
= (x/5)*(5/3)
= x/3
When calculating the number of self-help books why did you did x/5 - (1/3)*(x/5) and not x/5 - (1/3). It just says 1/3 less than the fiction books so this seems valid to me. But I couldn't get the correct answer. What am I missing?
