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A box contains 10 balls numbered from 1 to 10 inclusive. If : Multiple-choice Questions — Select One Answer Choice

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Re: A box contains 10 balls numbered from 1 to 10 inclusive. If [#permalink]
1
P(both women removed the same ball) = 1 - P(both women not removed the same ball)
= 1 - No of combinations in which both remove different balls/Total no of combinations
= 1 - 90/100 (Since Total no of combinations = 10*10 & No of combinations in which both remove different balls = 10*9)
= 10/100 = 1/10 (Ans)
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Re: A box contains 10 balls numbered from 1 to 10 inclusive. If [#permalink]
1
Trick question - don't fall for the trap that it has to be one specific ball that both must pick. Realise that it is whichever ball the first woman picks
Therefore, the probability is:
1*(1/10)=1/10 -> D
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Re: A box contains 10 balls numbered from 1 to 10 inclusive. If [#permalink]
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