Last visit was: 17 Jun 2024, 17:32 It is currently 17 Jun 2024, 17:32

Close

GRE Prep Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GRE score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Close

Request Expert Reply

Confirm Cancel
Retired Moderator
Joined: 16 Apr 2020
Status:Founder & Quant Trainer
Affiliations: Prepster Education
Posts: 1546
Own Kudos [?]: 2994 [6]
Given Kudos: 172
Location: India
WE:Education (Education)
Send PM
avatar
Intern
Intern
Joined: 27 Feb 2021
Posts: 1
Own Kudos [?]: 2 [2]
Given Kudos: 0
Send PM
Retired Moderator
Joined: 16 Apr 2020
Status:Founder & Quant Trainer
Affiliations: Prepster Education
Posts: 1546
Own Kudos [?]: 2994 [0]
Given Kudos: 172
Location: India
WE:Education (Education)
Send PM
Retired Moderator
Joined: 16 Apr 2020
Status:Founder & Quant Trainer
Affiliations: Prepster Education
Posts: 1546
Own Kudos [?]: 2994 [0]
Given Kudos: 172
Location: India
WE:Education (Education)
Send PM
Re: A certain circular stopwatch has exactly 60 second marks and a single [#permalink]
KarunMendiratta wrote:
A certain circular stopwatch has exactly 60 second marks and a single hand. If the hand of the watch is randomly set to one of the marks and allowed to count 10 seconds, what is the probability that the hand will stop less than 10 marks from the 53-second mark?

A. \(\frac{1}{6}\)
B. \(\frac{19}{60}\)
C. \(\frac{1}{3}\)
D. \(\frac{29}{60}\)
E. \(\frac{1}{2}\)


OA Explanation:

less than 10 marks from the 53-second mark: means it can go 9 marks ahead (3 second mark) or 9 marks before (44 second mark)
So, 44, 45, 46, 47, 48, 49, 50, 51, 52, 53, 54, 55, 56, 57, 58, 59, 60, 01, 02 (19 Marks)

Therefore, the required probability = \(\frac{19}{60}\)

Hence, option B
User avatar
GRE Prep Club Legend
GRE Prep Club Legend
Joined: 07 Jan 2021
Posts: 4602
Own Kudos [?]: 69 [0]
Given Kudos: 0
Send PM
Re: A certain circular stopwatch has exactly 60 second marks and a single [#permalink]
Hello from the GRE Prep Club BumpBot!

Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
Prep Club for GRE Bot
[#permalink]
Moderators:
Moderator
1088 posts
GRE Instructor
218 posts

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne