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A certain organization sells boxes of 32 oranges for $8.00 p
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19 Jun 2020, 09:51
19 Jun 2020, 09:51
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Question Stats:
80% (02:47) correct
20% (02:25) wrong based on 20 sessions
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A certain organization sells boxes of 32 oranges for $8.00 per box, boxes of 20 grapefruit for $7.00 per box, and combination boxes of oranges and grapefruit for $8.50 per box. If the unit price of each kind of fruit is independent of the kind of box in which it is packed and if each combination box contains twice as many oranges as grapefruit, how many grapefruit must be in a combination box?
A. 6
B. 7
C. 8
D. 10
E. 17
A. 6
B. 7
C. 8
D. 10
E. 17
Re: A certain organization sells boxes of 32 oranges for $8.00 p
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19 Jun 2020, 09:52
19 Jun 2020, 09:52
Expert Reply
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Re: A certain organization sells boxes of 32 oranges for $8.00 p
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19 Jun 2020, 09:58
19 Jun 2020, 09:58
1
Carcass wrote:
A certain organization sells boxes of 32 oranges for $8.00 per box, boxes of 20 grapefruit for $7.00 per box, and combination boxes of oranges and grapefruit for $8.50 per box. If the unit price of each kind of fruit is independent of the kind of box in which it is packed and if each combination box contains twice as many oranges as grapefruit, how many grapefruit must be in a combination box?
A. 6
B. 7
C. 8
D. 10
E. 17
A. 6
B. 7
C. 8
D. 10
E. 17
A certain organization sells boxes of 32 oranges for $8.00 per box, boxes of 20 grapefruit for $7.00 per box
Price PER ORANGE = $8.00/32 = $1/4 = $0.25
Price PER GRAPEFRUIT = $7.00/20 = $0.35
Each combination box contains TWICE as many oranges as grapefruit
Let G = the NUMBER of grapefruit in the box
So, 2G = the NUMBER of oranges in the box
Combination boxes of oranges and grapefruit for $8.50 per box
We can write: (G)(0.35) + (2G)($0.25) = 8.50
Simplify: 0.35G + 0.5G = 8.50
Simplify: 0.85G = 8.50
Solve: G = 8.50/0.85 = 10
So, there are 10 grapefruit in the combination box
Answer: D
Cheers,
Brent
