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Re: A certain taxi charges $0.85 for the first 1/2 mile and $0.2 [#permalink]
I support to Answer: A
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A certain taxi charges $ 0.85 for the first 1/2 mile and [#permalink]
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A certain taxi charges $ 0.85 for the first \(\frac{1}{2}\) mile and $ 0.25 for every \(\frac{1}{2}\) mile after that. The total cost of a trip was $ 8.85.

Quantity A
Quantity B
The trip’s distance in miles
16


A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
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Re: A certain taxi charges $ 0.85 for the first 1/2 mile and [#permalink]
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Carcass wrote:
A certain taxi charges $ 0.85 for the first \(\frac{1}{2}\) mile and $ 0.25 for every \(\frac{1}{2}\) mile after that. The total cost of a trip was $ 8.85.

Quantity A
Quantity B
The trip’s distance in miles
16


A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.


make an equation ...
let the distance be x miles after first 1/2 mile.. so there are 2x half miles
cost = \(0.85+2x*0.25=8.85.......0.5x=8......x=16\)

A. total distance = \(16+\frac{1}{2}\)
B. 16

A>B

A
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Re: A certain taxi charges $0.85 for the first 1/2 mile and $0.2 [#permalink]
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Hi,

I did it by using the equation:
8.85 = 0.85 + 0.25(x-1/2)
x = 32.5 miles.

Can someone tell me why this is wrong?
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Re: A certain taxi charges $0.85 for the first 1/2 mile and $0.2 [#permalink]
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Our focus is to solve the question. However, the normal path is to set up an equation like above by amorphous and from that to solve

However, it is just a matter of a simple proportion

IF we spend 0.50 dollars or a half dollar for 1 mile with 8 dollars how many miles wd o have ?

1:0.5=8:x

Solve for x this simple proportion and we do have 16 so the answer should be C

BUT we do have an additional half-mile so is 16+0.5=16.5

This is how much the taxi charged for the entire trip

A > B

Hope this helps
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Re: A certain taxi charges $0.85 for the first 1/2 mile and $0.2 [#permalink]
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gd2906 wrote:
Hi,

I did it by using the equation:
8.85 = 0.85 + 0.25(x-1/2)
x = 32.5 miles.

Can someone tell me why this is wrong?



Hi There!

I am not great with equations, let me try this one. The mistake in your equation is that 0.25 should be multiplied by 2 or 8 should be divided by 2.

The reason being we are calculating value for every 1 mile and not every 1/2 mile.

As you assumed let x be the total distance.
0.25 is the cost for 1/2 mile whereas we need the value of 1 mile.
Thus the value of travelling 1 mile=0.25+0.25=0.5

8= 0.5(x-1/2)
Solving for x we get 16.5

And as x is the total distance Qty A=16.5

Qty A>Qty B

Hope this helps
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A certain taxi charges $0.85 for the first 1/2 mile and $0.25 for ever [#permalink]
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A certain taxi charges $0.85 for the first 1/2 mile and $0.25 for every 1/2 mile after that. The total cost of a trip was $8.85


Quantity A
Quantity B
The trip's distance in miles
16



A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.


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A certain taxi charges $0.85 for the first 1/2 mile and $0.25 for ever [#permalink]
2
Let x= number of 1/2 miles after first 1/2mile
0.85+ 0.25(x)= 8.85
0.25(x) = 8.85-0.85
x= 8/0.25 , x= 32
Number of 1/2 miles after first is 32
Total distance = 1/2 +1/2(32)= 16.5 miles

Quantity A is greater

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Re: A certain taxi charges $0.85 for the first 1/2 mile and $0.2 [#permalink]
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