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A circle has radius x. What is its area?
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02 Jan 2022, 07:17
02 Jan 2022, 07:17
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Question Stats:
94% (00:16) correct
5% (00:09) wrong based on 19 sessions
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A circle has radius \(\sqrt{x}\). What is its area?
(A) \(\pi x\)
(B) \(2 \pi x\)
(C) \(2 \pi \sqrt{x}\)
(D) \(2 \pi x^2\)
(E) \(\pi x^2\)
(A) \(\pi x\)
(B) \(2 \pi x\)
(C) \(2 \pi \sqrt{x}\)
(D) \(2 \pi x^2\)
(E) \(\pi x^2\)
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Re: A circle has radius x. What is its area?
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02 Jan 2022, 07:22
02 Jan 2022, 07:22
Carcass wrote:
A circle has radius \(\sqrt{x}\). What is its area?
(A) \(\pi x\)
(B) \(2 \pi x\)
(C) \(2 \pi \sqrt{x}\)
(D) \(2 \pi x^2\)
(E) \(\pi x^2\)
(A) \(\pi x\)
(B) \(2 \pi x\)
(C) \(2 \pi \sqrt{x}\)
(D) \(2 \pi x^2\)
(E) \(\pi x^2\)
Area of circle \(= \pi r^2\)
Substitute \(x\) for the radius to get: area \(= \pi (\sqrt{x})^2\)
Simplify: area \(= \pi x\)
Answer: A
gmatclubot
Re: A circle has radius x. What is its area? [#permalink]
02 Jan 2022, 07:22
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