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A circle of area 49 is divided into n equal sectors forming arcs of
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05 May 2023, 07:22
05 May 2023, 07:22
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Question Stats:
85% (01:42) correct
14% (02:12) wrong based on 7 sessions
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A circle of area \(49 \pi\) is divided into ‘n’ equal sectors forming arcs of length \(\frac{7 \pi}{5}\) each. What is the area of one of the sectors?
\(\frac{7 \pi}{10}\)
\(\frac{7 \pi}{5}\)
\(\frac{14 \pi}{5}\)
\(\frac{49 \pi}{10}\)
\(\frac{49 \pi}{5}\)
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\(\frac{7 \pi}{10}\)
\(\frac{7 \pi}{5}\)
\(\frac{14 \pi}{5}\)
\(\frac{49 \pi}{10}\)
\(\frac{49 \pi}{5}\)
Post A Detailed Correct Solution For The Above Questions And Get A Kudos.
Question From Our Project: Free GRE Prep Club Tests in Exchange for 20 Kudos
\(\Longrightarrow\) GRE - Quant Daily Topic-wise Challenge
\(\Longrightarrow\) GRE GEOMETRY
Re: A circle of area 49 is divided into n equal sectors forming arcs of
[#permalink]
05 May 2023, 07:48
05 May 2023, 07:48
1
pi * r^2 = 49pi
r = 7
2 * pi * r/n = 7 * pi / 5
n = 10 sectors
Area of one sector = 49 Pi / 10
r = 7
2 * pi * r/n = 7 * pi / 5
n = 10 sectors
Area of one sector = 49 Pi / 10
gmatclubot
Re: A circle of area 49 is divided into n equal sectors forming arcs of [#permalink]
05 May 2023, 07:48
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