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Re: A computer manufacturer builds 1,000 computers and all of th [#permalink]
Carcass wrote:
I am not sure if I understood your question. However, we can figure out what the question is asking for: the cost of ONE computer.

If the profit (which is the Revenue minus the costs for the computer) is 20,000 and it is 40% of the costs we can solve

\(20,000=0.4x \)

\(x = 50,000
\)

if the profit are 20,000 and the costs are 50,000 the total operation at the retail level amount to 70,000.

So \(\frac{70,000}{1,000 }= 70\)

One computer costs 70 dollars

A is greater


Hope this helps


I was just wondering if $50 would be the production cost of one unit. I guess it is correct.
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Re: A computer manufacturer builds 1,000 computers and all of th [#permalink]
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theBrahmaTiger wrote:
Carcass wrote:
I am not sure if I understood your question. However, we can figure out what the question is asking for: the cost of ONE computer.

If the profit (which is the Revenue minus the costs for the computer) is 20,000 and it is 40% of the costs we can solve

\(20,000=0.4x \)

\(x = 50,000
\)

if the profit are 20,000 and the costs are 50,000 the total operation at the retail level amount to 70,000.

So \(\frac{70,000}{1,000 }= 70\)

One computer costs 70 dollars

A is greater


Hope this helps


I was just wondering if $50 would be the production cost of one unit. I guess it is correct.


yes. Correct
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Re: A computer manufacturer builds 1,000 computers and all of th [#permalink]
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