Here
\(\frac{4 quarts of Alcohol}{4 quarts of water}\)

we need to add water to above solution to make it equal to = \(\frac{3 parts of Alcohol}{5 parts of water}\)
Let w= quarts of water required

Total quarts of water = (4 + w)

Therefore we can re write as -

\(\frac{4 quarts of Alcohol}{(4 quarts of water + w)}\) = \(\frac{3 parts of Alcohol}{5 parts of water}\)(since we need to add w to make the ratio equal to 3/5)

or \(\frac{4}{(4+w)}\) =\(\frac{3}{5}\)

or w =\(\frac{8}{3}\)
_________________

We can create the following equation in which n = the added water:

4/(4 + n) = 3/5

20 = 12 + 3n

8 = 3n

8/3 = n

Answer: D
_________________

A container holds 4 quarts of alcohol and 4 quarts of water. How many quarts of water must be added to the container to create a mixture that is 3 parts alcohol to 5 parts water by volume?

A. \(\frac{4}{3}\)

B. \(\frac{5}{3}\)

C. \(\frac{7}{3}\)

D. \(\frac{8}{3}\)

E. \(\frac{10}{3}\)
_________________

4/(4+x) = 3/5

20 = 12 + 3x

8 = 3x

X = 8/3

Hello from the GRE Prep Club BumpBot!

Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.