Last visit was: 26 Apr 2024, 03:11 It is currently 26 Apr 2024, 03:11

Close

GRE Prep Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GRE score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Close

Request Expert Reply

Confirm Cancel
Verbal Expert
Joined: 18 Apr 2015
Posts: 28638
Own Kudos [?]: 33129 [0]
Given Kudos: 25178
Send PM
Verbal Expert
Joined: 18 Apr 2015
Posts: 28638
Own Kudos [?]: 33129 [0]
Given Kudos: 25178
Send PM
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Own Kudos [?]: 11687 [3]
Given Kudos: 136
Send PM
Intern
Intern
Joined: 02 Mar 2022
Posts: 17
Own Kudos [?]: 4 [0]
Given Kudos: 37
Send PM
Re: A driver completed the first 20 miles of a 40-mile trip at a [#permalink]
Tough problem, but good explanation!
Manager
Manager
Joined: 19 Jun 2021
Posts: 52
Own Kudos [?]: 25 [1]
Given Kudos: 24
Send PM
Re: A driver completed the first 20 miles of a 40-mile trip at a [#permalink]
1
I am trying to solve it with a weighted average but it doesn't work. Can you please take a look at why my method doesn't work?

First, I find the time it takes to drive all 40 miles knowing that the average is 60.
40/60 = 2/3

Now I find the time it takes to pass the first 20 miles.
20/50 = 2/5

Then I find the time it takes to pass the rest 20 miles.

2/3 - 2/5 = 4/15

Now calculate using the weighted average:
(2/5)*50 + (4/15)*X = 60

20 + (4/15)*X = 60

(4/15)*X = 40

(1/15)*X = 10

X = 150

Where is my mistake here?
Manager
Manager
Joined: 19 Jun 2021
Posts: 52
Own Kudos [?]: 25 [1]
Given Kudos: 24
Send PM
Re: A driver completed the first 20 miles of a 40-mile trip at a [#permalink]
1
Paul121 wrote:
I am trying to solve it with a weighted average but it doesn't work. Can you please take a look at why my method doesn't work?

First, I find the time it takes to drive all 40 miles knowing that the average is 60.
40/60 = 2/3

Now I find the time it takes to pass the first 20 miles.
20/50 = 2/5

Then I find the time it takes to pass the rest 20 miles.

2/3 - 2/5 = 4/15

Now calculate using the weighted average:
(2/5)*50 + (4/15)*X = 60

20 + (4/15)*X = 60

(4/15)*X = 40

(1/15)*X = 10

X = 150

Where is my mistake here?




I think that I figured out my mistake. It should be:
(2/5)/(2/3)*50 + (4/15)/(2/3)*X = 60
Instead of:
(2/5)*50 + (4/15)*X = 60
Prep Club for GRE Bot
[#permalink]
Moderators:
Moderator
1085 posts
GRE Instructor
218 posts

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne