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a et b = a^2-ab

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Carcass
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a et b = a^2-ab [#permalink] New post   02 Jan 2021, 10:43
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\(a \Cup b = a^2-ab\)


Quantity A
Quantity B
\(4 \Cup 3\)
\(3 \Cup 4\)



A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.

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Ashgre
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Re: a et b = a^2-ab [#permalink] New post   03 Jan 2021, 03:08
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Carcass wrote:
\(a \Cup b = a^2-ab\)


Quantity A
Quantity B
\(4 \Cup 3\)
\(3 \Cup 4\)



A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.

Kudos for the right answer and explanation


Given condition is: a⋓b = a^2 − ab.

Qty A: 4⋓3 = 4^2 - 4x3 --> 16 - 12 => 4.

Qty B: 3⋓4 = 3^2 - 3x4 --> 9 - 12 => -3.

Hence Qty A is greater.
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gmatclubot
Re: a et b = a^2-ab [#permalink]
03 Jan 2021, 03:08
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