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A gardener plants two rectangular gardens in separate regions on her p
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04 Jan 2023, 10:18
04 Jan 2023, 10:18
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Question Stats:
85% (02:10) correct
14% (04:59) wrong based on 7 sessions
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A gardener plants two rectangular gardens in separate regions on her property. The first garden has an area of 600 square feet and a length of 40 feet. If the second garden has a width twice that of the first garden, but only half the area, what is the ratio of the perimeter of the first garden to that of the second garden?
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110/80
Re: A gardener plants two rectangular gardens in separate regions on her p
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30 Jan 2023, 11:20
30 Jan 2023, 11:20
Expert Reply
OE
According to the problem, the first garden has an area of 600 square feet and a length of 40 feet. Therefore, the width of the garden is 600/40=15 feet The second garden has a width twice that amount (30 feet), and an area
only half that of the first garden 1/2 of 600.
the length of the second garden is 300/30=10 feet
The perimeter of the first garden is 2 x length + 2 x width = 2(40) + 2(15) = 110.
The perimeter of the second garden is 2 x length + 2 x width = 2(10) + 2(30) = 80.
The correct ration is 110/80
According to the problem, the first garden has an area of 600 square feet and a length of 40 feet. Therefore, the width of the garden is 600/40=15 feet The second garden has a width twice that amount (30 feet), and an area
only half that of the first garden 1/2 of 600.
the length of the second garden is 300/30=10 feet
The perimeter of the first garden is 2 x length + 2 x width = 2(40) + 2(15) = 110.
The perimeter of the second garden is 2 x length + 2 x width = 2(10) + 2(30) = 80.
The correct ration is 110/80
gmatclubot
Re: A gardener plants two rectangular gardens in separate regions on her p [#permalink]
30 Jan 2023, 11:20
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