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A group of x applicants is to be chosen for a spot on a tele
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10 Oct 2017, 20:19
10 Oct 2017, 20:19
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Question Stats:
16% (01:51) correct
83% (02:10) wrong based on 59 sessions
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A group of x applicants is to be chosen for a spot on a television show. The number of applicants chosen, y, can range from 1 to x. If there are a total of 56 different possible selections for the spot on the television show, which of the following are possible values of y? (Choose all that apply.)
(A) 1
(B) 3
(C) 5
(D) 7
(E) 8
(F) 28
(G) 55
(H) 56
OA:
Kudos for correct solution.
(A) 1
(B) 3
(C) 5
(D) 7
(E) 8
(F) 28
(G) 55
(H) 56
OA:
Show: ::
(A), (B), (C), and (G)
Kudos for correct solution.
ShowHide Answer
Official Answer
A,B,C,G
Re: A group of x applicants is to be chosen for a spot on a tele
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10 Oct 2017, 21:55
10 Oct 2017, 21:55
3
Bunuel wrote:
A group of x applicants is to be chosen for a spot on a television show. The number of applicants chosen, y, can range from 1 to x. If there are a total of 56 different possible selections for the spot on the television show, which of the following are possible values of y? (Choose all that apply.)
Now we have xCy = 56
where y= 1 to x
Let us consider the options which are mentioned whose combination equals to 56
56 = 7 * 8 or 14 * 4 or 28 * 2 or 56 * 1
Let x= 56 and y = 1
therefore 56C1 = 56
Let x= 8 and y= 3
therefore 8C3 = 56
Let x= 8 and y= 5
Therefore 8C5 = 56
Let x = 56 and y = 55
Therefore 56C55 = 56
Hence when y= 1 , 3, 5 and 55 then the combination equals to 56
i. e option A, option B, option C and option G
Re: A group of x applicants is to be chosen for a spot on a tele
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24 Nov 2017, 14:51
24 Nov 2017, 14:51
Is there a fast way of doing this....I feel like on an actual exam, having to go through the calculations of this will take too much time....Thanks!
