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A hat contains 12 cards marked with a star and 18 unmarked cards. What
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28 Sep 2021, 09:30
28 Sep 2021, 09:30
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64% (00:31) correct
35% (00:37) wrong based on 34 sessions
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A hat contains 12 cards marked with a star and 18 unmarked cards. What is the probability that one card selected at random will be marked with a star?
A. 2/5
B. 3/5
C. 2/3
D. 3/2
E. 5/2
A. 2/5
B. 3/5
C. 2/3
D. 3/2
E. 5/2
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Re: A hat contains 12 cards marked with a star and 18 unmarked cards. What
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28 Sep 2021, 09:50
28 Sep 2021, 09:50
Carcass wrote:
A hat contains 12 cards marked with a star and 18 unmarked cards. What is the probability that one card selected at random will be marked with a star?
A. 2/5
B. 3/5
C. 2/3
D. 3/2
E. 5/2
A. 2/5
B. 3/5
C. 2/3
D. 3/2
E. 5/2
We can solve this by applying the general probability formula:
P(event A occurs) = (# of outcomes where event A occurs)/(total # of outcomes)
So, P(marked card) = (# of outcomes in which we get a marked card)/(total # of outcomes)
There are 12 marked cards. So, there are 12 possible outcomes in which we get a marked card
There are 30 cards altogether (12 marked + 18 unmarked = 30 in total). So, there are 30 possible outcomes.
So, P(marked card) = 12/30
= 2/5
Answer: A
Re: A hat contains 12 cards marked with a star and 18 unmarked cards. What
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11 Jul 2024, 13:51
11 Jul 2024, 13:51
Hello from the GRE Prep Club BumpBot!
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Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
