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a is different from zero

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Carcass
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a is different from zero [#permalink] New post   01 Jun 2022, 02:00
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\(a \neq 0\)


Quantity A
Quantity B
\(a+b^2\)
\((a+b)^2-2ab\)



A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given

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D
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GreenlightTestPrep
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Re: a is different from zero [#permalink] New post   01 Jun 2022, 05:04
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Carcass wrote:
\(a \neq 0\)

Quantity A
Quantity B
\(a+b^2\)
\((a+b)^2-2ab\)



We can solve this question using matching operations (see the video lesson below )
Given:
Quantity A: \(a+b^2\)
Quantity B: \((a+b)^2-2ab\)

Expand and simplify Quantity B:
Quantity A: \(a+b^2\)
Quantity B: \(a^2+b^2\)

Subtract \(b^2\) from both quantities:
Quantity A: \(a\)
Quantity B: \(a^2\)

At this point we can see that, if \(a = 1\), the two quantities are equal
Conversely, if \(a = 2\), the two quantities are not equal

Answer: D

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Re: a is different from zero [#permalink]
01 Jun 2022, 05:04
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