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A is the center of the top face of the right circular cylind
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25 Nov 2020, 09:33
25 Nov 2020, 09:33
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57% (02:41) correct
42% (02:16) wrong based on 21 sessions
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GRE A is the center of the top face of the right circular cylinder.jpg [ 22.98 KiB | Viewed 2799 times ]
\(A\) is the center of the top face of the right circular cylinder in the figure above. If the degree measure of \(∠BAC\) is four times that of \(∠ACB\), and the height of the cylinder is equal to the diameter of its base, then the volume of the shaded region is what fraction of the volume of the entire cylinder?
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\(\frac{1}{3}\)
Re: A is the center of the top face of the right circular cylind
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28 Nov 2020, 23:58
28 Nov 2020, 23:58
1/3!
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Re: A is the center of the top face of the right circular cylind
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29 Nov 2020, 04:45
29 Nov 2020, 04:45
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lets say ∠ACB=x, therefore ∠BAC=4x, ∠ABC=x (△ABC is Isosceles)
x+4x+x=180° , x= 30° ,therefore ∠BAC=120°
Volume proportion of shaded region to entire Cylinder= 120/360 =1/3
x+4x+x=180° , x= 30° ,therefore ∠BAC=120°
Volume proportion of shaded region to entire Cylinder= 120/360 =1/3
