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A + L =130, where A is the area of a rectangle and L is the length of
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05 Feb 2025, 00:09
05 Feb 2025, 00:09
Expert Reply
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Question Stats:
83% (01:34) correct
16% (01:48) wrong based on 6 sessions
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A + L =130, where A is the area of a rectangle and L is the length of one side of the same rectangle. If the length of other side of the rectangle is 6, what is the value of A?
A. 100
B. 111.42
C. 122.28
D. 125
E. 130
A. 100
B. 111.42
C. 122.28
D. 125
E. 130
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Re: A + L =130, where A is the area of a rectangle and L is the length of
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06 Mar 2025, 11:10
06 Mar 2025, 11:10
Expert Reply
Let the two sides of the rectangle be $\(L\)$ \& $\(B\)$, out of which $\(B\)$ is given as 6
We are given that $\(A+L=130\)$, where $\(A\)$ is the area of the rectangle and $\(L\)$ is the side, so we get $\(L \times B+L=130\)$ i.e. $\(L \times 6+L=130\)$ which gives $\(7 L=130 \Rightarrow L=\frac{130}{7}\)$
So, the value of A i.e. the area of the rectangle is $\(\mathrm{L} \times \mathrm{B}=\frac{130}{7} \times 6=\frac{780}{7} \sim 111.4\)$
Hence the answer is (B).
We are given that $\(A+L=130\)$, where $\(A\)$ is the area of the rectangle and $\(L\)$ is the side, so we get $\(L \times B+L=130\)$ i.e. $\(L \times 6+L=130\)$ which gives $\(7 L=130 \Rightarrow L=\frac{130}{7}\)$
So, the value of A i.e. the area of the rectangle is $\(\mathrm{L} \times \mathrm{B}=\frac{130}{7} \times 6=\frac{780}{7} \sim 111.4\)$
Hence the answer is (B).
gmatclubot
Re: A + L =130, where A is the area of a rectangle and L is the length of [#permalink]
06 Mar 2025, 11:10
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