Re: A + L =130, where A is the area of a rectangle and L is the length of
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06 Mar 2025, 11:10
Let the two sides of the rectangle be $\(L\)$ \& $\(B\)$, out of which $\(B\)$ is given as 6
We are given that $\(A+L=130\)$, where $\(A\)$ is the area of the rectangle and $\(L\)$ is the side, so we get $\(L \times B+L=130\)$ i.e. $\(L \times 6+L=130\)$ which gives $\(7 L=130 \Rightarrow L=\frac{130}{7}\)$
So, the value of A i.e. the area of the rectangle is $\(\mathrm{L} \times \mathrm{B}=\frac{130}{7} \times 6=\frac{780}{7} \sim 111.4\)$
Hence the answer is (B).