The volume of each bowl $\(=\frac{1}{2} \times \frac{4}{3} \pi\left(r_2^2-r_1^2\right)=\frac{4}{3} \frac{\pi\left(14^3-7^3\right)}{2}\)$ and

The volume of the cylinder $\(\left(\pi r^2 h\right)=\pi \times 7^2 \times 98\)$.

Therefore, the number of bowls that can be drawn from the cylinder $\(=\frac{\pi \times 49 \times 98 \times 3 \times 2}{4 \times \pi \times 2401}=3\)$.
Thus, the correct answer is $\(B\)$.