Carcass wrote:
A milliner bought a job lot of hats 1/4 of which were brown. The milliner sold 2/3 of the hats including 4/5 of the brown hats. What fraction of the unsold hats were brown?
(A) 1/60
(B) 2/15
(C) 3/20
(D) 3/5
(E) 3/4
STRATEGY CHECK: One option here is to let x = the total number of hats, and then calculate each value in terms of x.
Another option is to assign a "nice" to the total number of hats (i.e., a number that works well with all of the fractions)Let's take the second approach.
The least common multiple of the three denominators (4, 3 and 5) is
60So, let's say there are
60 hats in the job lot.
A milliner bought a job lot of (60) hats 1/4 of which were brown.1/4 of
60 = 15, which means there were
15 brown hats in the job lot.
The milliner sold 2/3 of the hats including 4/5 of the brown hats.2/3 of
60 = 40, which means the milliner sold a total of 40 hats, and
20 hats remained unsold
4/5 of
15 = 12, which means the milliner sold a total of 12 brown hats, and
3 brown hats remained unsold
What fraction of the unsold hats were brown?3 of the
20 unsold hats were brown.
Answer = 3/20 = C