Re: A piggy-bank contains a certain number of coins, of which 53
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Updated on: 25 Apr 2020, 10:31
A piggy-bank contains a certain number of coins, of which 53 are dimes and 19 are nickels. The remainder of the coins in the bank are quarters. If the probability of selecting a quarter from this bank is 1/4, how many quarters does the bank contain?
Total Coins= A
#Dimes=53
#Nickles=19
Total Quarters=(Total Coins-#Dimes-#Nickles)
P(Quarters)= P(Success/Total Outcomes)= (Total Quarters/ Total coins)=1/4
P=(Total Quarters/Total Coins)= (A-53-19)/A = 1/4
4(A-72)=A
4A-228=A
3A=228
A=96-->
Total Quarters=(Total Coins-#Dimes-#Nickles)
Quartes = 96-53-19
Quartes =24
Option C
Originally posted by
JzContecha on 25 Apr 2020, 10:21.
Last edited by
JzContecha on 25 Apr 2020, 10:31, edited 9 times in total.