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Re: A play has two roles for men and four roles for women. If five men and [#permalink]
Carcass wrote:
The first male role can be filled by any of the five men, and the second by any of the remaining 4, for a total of 5 * 4 = 20 choices. Similarly, there are 12 options for the first female role, 11 for the next, 10 for the third, and 9 for the last. The total number of possibilities is thus 5 * 4 * 12 * 11 * 10 * 9 = 237,600.


I get this answer when I account for arrangement in 5c2* 2! * 12c4 *4!
but this is not asking for arrangement, question mentions how director can chose among the 5 men for the two roles..in addition to this since it is not mentioned the roles are distinct won't we be double counting
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Re: A play has two roles for men and four roles for women. If five men and [#permalink]
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volcanictempest78 wrote:
Carcass wrote:
The first male role can be filled by any of the five men, and the second by any of the remaining 4, for a total of 5 * 4 = 20 choices. Similarly, there are 12 options for the first female role, 11 for the next, 10 for the third, and 9 for the last. The total number of possibilities is thus 5 * 4 * 12 * 11 * 10 * 9 = 237,600.


I get this answer when I account for arrangement in 5c2* 2! * 12c4 *4!
but this is not asking for arrangement, question mentions how director can chose among the 5 men for the two roles..in addition to this since it is not mentioned the roles are distinct won't we be double counting


Sir

the explanation above is a fundamental counting principle

You must choose five men and then four. you do not have any sort of constraint

The same for the women

Regards
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Re: A play has two roles for men and four roles for women. If five men and [#permalink]
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volcanictempest78 wrote:
Carcass wrote:
The first male role can be filled by any of the five men, and the second by any of the remaining 4, for a total of 5 * 4 = 20 choices. Similarly, there are 12 options for the first female role, 11 for the next, 10 for the third, and 9 for the last. The total number of possibilities is thus 5 * 4 * 12 * 11 * 10 * 9 = 237,600.


I get this answer when I account for arrangement in 5c2* 2! * 12c4 *4!
but this is not asking for arrangement, question mentions how director can chose among the 5 men for the two roles..in addition to this since it is not mentioned the roles are distinct won't we be double counting


I agree. The author could have added a few extra words to inform us that the 6 roles are distinct/different.
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Re: A play has two roles for men and four roles for women. If five men and [#permalink]
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For me, there is not so much room for misinterpretation...................
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Re: A play has two roles for men and four roles for women. If five men and [#permalink]
Carcass wrote:
The first male role can be filled by any of the five men, and the second by any of the remaining 4, for a total of 5 * 4 = 20 choices. Similarly, there are 12 options for the first female role, 11 for the next, 10 for the third, and 9 for the last. The total number of possibilities is thus 5 * 4 * 12 * 11 * 10 * 9 = 237,600.

Would you please enlighten me why it is not 5*4 + 12*11*10*9 ?
Aren't men and female roles are two separate entities?
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Re: A play has two roles for men and four roles for women. If five men and [#permalink]
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A play has two roles for men and four roles for women

and = multiplication
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