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Re: A plumber is twice efficient than his apprentice. After the plumber [#permalink]
KarunMendiratta wrote:
Explanation:

More efficient means less time or more work!

Let us assume it takes the plumber alone \(x\) hours to finish the job
So his apprentice would require \(2x\) hours to finish the same job

Work done by Plumber + Work done by the apprentice = 1
\(W_p + W_a = 1\)

The plumber has worked for a total of \(5\) hours whereas, his apprentice worked for \(3\) hours only
i.e. \(\frac{5}{x} + \frac{3}{2x} = 1\)
\(13 = 2x\)
\(x = 6.5\)

Col. A: \(2(6.5) = 13\)
Col. B: \(10\)

Hence, option A


Excellent solution!
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Re: A plumber is twice efficient than his apprentice. After the plumber [#permalink]
1
In total, the plumber worked 5 hours, and the apprentice worked 3 hours.
If the apprentice did it alone, he would put in twice the time the plumber put in, plus the time the apprentice already put in, which is 2*5 +3 = 13 hours.

So A is bigger.
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Re: A plumber is twice efficient than his apprentice. After the plumber [#permalink]
I don't like the wording, honestly! Because "finish the job" could mean how long would it take for the apprentice to finish (working alone) if the plumber left after two hours. In that case, the answer is 9. Which is annoying. So, hopefully on the test it is a bit clearer.
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Re: A plumber is twice efficient than his apprentice. After the plumber [#permalink]
Hello from the GRE Prep Club BumpBot!

Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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