Last visit was: 24 Apr 2024, 21:11 It is currently 24 Apr 2024, 21:11

Close

GRE Prep Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GRE score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Close

Request Expert Reply

Confirm Cancel
User avatar
Retired Moderator
Joined: 07 Jun 2014
Posts: 4810
Own Kudos [?]: 10616 [0]
Given Kudos: 0
GRE 1: Q167 V156
WE:Business Development (Energy and Utilities)
Send PM
avatar
Active Member
Active Member
Joined: 29 May 2018
Posts: 126
Own Kudos [?]: 148 [2]
Given Kudos: 0
Send PM
avatar
Intern
Intern
Joined: 08 Apr 2018
Posts: 44
Own Kudos [?]: 20 [0]
Given Kudos: 0
Send PM
User avatar
Retired Moderator
Joined: 07 Jun 2014
Posts: 4810
Own Kudos [?]: 10616 [0]
Given Kudos: 0
GRE 1: Q167 V156
WE:Business Development (Energy and Utilities)
Send PM
Re: A population of a colony of bacteria increases by 20 [#permalink]
Expert Reply
Explanation

Every 3 minutes, the population increases by 20% (which is the same as multiplying by 1.2).

Beginning at 8:54am, this change would occur at 8:57am and again at 9:00am. Use the variable x to represent the original quantity. Note that the 20% increase occurs twice:

x(1.2)(1.2) = 144,000
x = 100,000

Note that you cannot just reduce 144,000 by 20% twice, because 20% is not a percent of 144,000—it is a percent of the unknown, original number.

Alternatively, begin from 144,000 and calculate “backwards”:

From 8:57am to 9:00am: y(1.2) = 144,000, so y =\(\frac{144,000}{1.2}\) = 120,000.

From 8:54am to 8:57am: z(1.2) = 120,000, so z = \(\frac{120,000}{1.2}\)= 100,000.
Manager
Manager
Joined: 06 Jun 2018
Posts: 102
Own Kudos [?]: 120 [0]
Given Kudos: 4
Send PM
Re: A population of a colony of bacteria increases by 20 [#permalink]
sandy wrote:
A population of a colony of bacteria increases by 20 percent every 3 minutes. If at 9:00am the colony had a population of 144,000, what was the population of the colony at 8:54am?

(A) 100,000
(B) 112,000
(C) 120,000
(D) 121,000
(E) 136,000



Total time span : 6 mins. So there will be 2 phases.

Increase rate : 20% in every 3 minutes. That can be expressed as follows :

\((1.2)^2\).

let assume the number of bacteria at the very beginning was x.

x*(1.2)^2= 144000

x = 144000 / 1.44

x = 14400000 / 144

x = 100000.

The best answer is A.
Intern
Intern
Joined: 30 Oct 2021
Posts: 30
Own Kudos [?]: 10 [0]
Given Kudos: 25
Send PM
Re: A population of a colony of bacteria increases by 20 [#permalink]
I tried doing a decrease of 20% from 144000 but this method didn't work. Can someone explain why?
Retired Moderator
Joined: 02 Dec 2020
Posts: 1833
Own Kudos [?]: 2118 [2]
Given Kudos: 140
GRE 1: Q168 V157

GRE 2: Q167 V161
Send PM
A population of a colony of bacteria increases by 20 [#permalink]
2
If you decrease it by \(20\)%, it means that the value will be \(80\)%.

Let's say a value is 100. Now it increases every day by \(20\)%. So the next day it will be \(120\).

Now if we want to get the value on the first day, while decreasing with your method, it will be \(80\)% of \(120 = \)96

So for the \(20\)% decrease, we have to divide by \(1.20\),a multiplier, to get the correct value.

Please ask if the doubt remains.

Greprep911 wrote:
I tried doing a decrease of 20% from 144000 but this method didn't work. Can someone explain why?
User avatar
GRE Prep Club Legend
GRE Prep Club Legend
Joined: 07 Jan 2021
Posts: 4414
Own Kudos [?]: 68 [0]
Given Kudos: 0
Send PM
Re: A population of a colony of bacteria increases by 20 [#permalink]
Hello from the GRE Prep Club BumpBot!

Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
Prep Club for GRE Bot
[#permalink]
Moderators:
Moderator
1085 posts
GRE Instructor
218 posts

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne