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A regular polygon will be drawn with a number of sides randomly chosen
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04 Apr 2022, 02:30
04 Apr 2022, 02:30
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Question Stats:
85% (02:04) correct
14% (01:20) wrong based on 7 sessions
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A regular polygon will be drawn with a number of sides randomly chosen from the whole numbers 3 through 10. What is the probability that the internal angles will be greater than 110°?
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5/8
Part of the project: GRE Quantitative Reasoning Daily Challenge - (2022) EDITION
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GRE Math Essentials for a TOP Quant Score - Q170!!! (2021)
GRE Geometry Formulas for a Q170
GRE - Math Book
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
GRE Math Essentials for a TOP Quant Score - Q170!!! (2021)
GRE Geometry Formulas for a Q170
GRE - Math Book
Re: A regular polygon will be drawn with a number of sides randomly chosen
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07 Apr 2022, 04:48
07 Apr 2022, 04:48
1
Number of regular polygon that can be drawn with a number of sides 3 through 10 = 8
Using the formula to calculate internal angle of regular polygon = (n-2)*180/n
When n = 6, measure of internal angles = 4*180/6 = 120
Regular polygon with a number of sides from 6 through 10 will have internal angles will be greater than 110°
Hence, there are 5 regular polygons
Required probability = 5/8
Takeaway: Formula to calculate internal angles of regular polygon = (n-2)*180/n
Using the formula to calculate internal angle of regular polygon = (n-2)*180/n
When n = 6, measure of internal angles = 4*180/6 = 120
Regular polygon with a number of sides from 6 through 10 will have internal angles will be greater than 110°
Hence, there are 5 regular polygons
Required probability = 5/8
Takeaway: Formula to calculate internal angles of regular polygon = (n-2)*180/n
gmatclubot
Re: A regular polygon will be drawn with a number of sides randomly chosen [#permalink]
07 Apr 2022, 04:48
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