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A set of numbers has the property that for any number t in the set, t
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17 Nov 2022, 04:07
17 Nov 2022, 04:07
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Expert Reply
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Question Stats:
33% (00:48) correct
66% (00:56) wrong based on 9 sessions
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A set of numbers has the property that for any number t in the set, t + 2 is in the set. If –1 is in the set, which of the following must also be in the set?
I. –3
II. 1
III. 5
A. I only
B. II only
C. I and II only
D. II and III only
E. I, II, and III
I. –3
II. 1
III. 5
A. I only
B. II only
C. I and II only
D. II and III only
E. I, II, and III
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Free Materials for the GRE General Exam - Where to get it!!
GRE Geometry Formulas
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GRE Whiz Representative
Joined: 25 May 2022
Posts: 25
Given Kudos: 1
Re: A set of numbers has the property that for any number t in the set, t
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19 Nov 2022, 04:16
19 Nov 2022, 04:16
1
Expert Reply
The constraint suggests that if 't' is present then 't+2' must be present.
Now coming to the question,
1. if - 1 is present then - 1 + 2 = 1 must be present.
2. If 1 is present then 1 + 2 = 3 must be present and so on
So the set must have - 1, 1, 3, 5, ... so on.
One may think that since - 1 is there so - 3 must be there. But that is not what the constraint states. The mere presence of -1 does not mean - 3 will be there.
So other I, the other two (II, III) must be true. 'I' can be true but NOT must.
The answer is D.
Now coming to the question,
1. if - 1 is present then - 1 + 2 = 1 must be present.
2. If 1 is present then 1 + 2 = 3 must be present and so on
So the set must have - 1, 1, 3, 5, ... so on.
One may think that since - 1 is there so - 3 must be there. But that is not what the constraint states. The mere presence of -1 does not mean - 3 will be there.
So other I, the other two (II, III) must be true. 'I' can be true but NOT must.
The answer is D.
gmatclubot
Re: A set of numbers has the property that for any number t in the set, t [#permalink]
19 Nov 2022, 04:16
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