Carcass wrote:
koala wrote:
Carcass wrote:
let x=total units of original solution
let w=units of water evaporated
.9x-w=.6(x-w)→
x/w=4/3
substituting,
initial water weight=.9*4=3.6
final water weight=.9*4-3=.6
3.6/.6=6:1
E
How can we substitute x=4 and y=3 in
initial water weight=.9*4=3.6
final water weight=.9*4-3=.6as it's just a ratio
x/w=4/3sorry sir what is your question??
You substituted values of x and y in these equations
initial water weight=.9*4=3.6
final water weight=.9*4-3=.6
but you stated
x/w=4/3 earlier and if that's a ratio of x and w, how can we take 4 and 3 as their value?