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A square with an area equal to 256 has its center at the
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Updated on: 23 Nov 2019, 17:23
Updated on: 23 Nov 2019, 17:23
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Question Stats:
68% (39:08) correct
32% (02:49) wrong based on 50 sessions
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A square with an area equal to 256 has its center at the origin, (0,0), in the xy-coordinate plane. The graph of a function f is defined by \(f(x)=cx^3\), for some positive constant c, intersects the square at two opposite vertices of the square. What is the value of C? (Enter your answer as a fraction?)
Show: :: OA
\(\frac{1}{64}\)
Re: A square with an area equal to 256 has its center at the
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06 Oct 2019, 01:56
06 Oct 2019, 01:56
2
Possible intersections points: (8,8) or (-8,-8)
So given x=8, y=8 and for function f(x=8) = c*8*8*8
c*8*8*8 = 8
=> c = 1/64
So given x=8, y=8 and for function f(x=8) = c*8*8*8
c*8*8*8 = 8
=> c = 1/64
Re: A square with an area equal to 256 has its center at the
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19 Nov 2019, 08:25
19 Nov 2019, 08:25
2
1
gagangm wrote:
Can anyone tell me? What does it mean by intersects the square at two opposite vertices of the square?
Here's an example of a curve (in red) intersecting two opposite vertices of a square:
Cheers,
Brent
_________________
Re: A square with an area equal to 256 has its center at the
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19 Nov 2019, 08:26
19 Nov 2019, 08:26
1
Expert Reply
Re: A square with an area equal to 256 has its center at the
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23 Nov 2019, 17:17
23 Nov 2019, 17:17
luffy wrote:
Possible intersections points: (8,8) or (-8,-8)
So given x=8, y=8 and for function f(x=8) = c*8*8*8
c*8*8*8 = 8
=> c = 1/64
So given x=8, y=8 and for function f(x=8) = c*8*8*8
c*8*8*8 = 8
=> c = 1/64
how do you know that the possible intersections points are (8,8) or (-8,-8)?
Why not other pairs (4,4), (-4,-4)?
Re: A square with an area equal to 256 has its center at the
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20 Jan 2020, 05:11
20 Jan 2020, 05:11
2
mouda wrote:
luffy wrote:
Possible intersections points: (8,8) or (-8,-8)
So given x=8, y=8 and for function f(x=8) = c*8*8*8
c*8*8*8 = 8
=> c = 1/64
So given x=8, y=8 and for function f(x=8) = c*8*8*8
c*8*8*8 = 8
=> c = 1/64
how do you know that the possible intersections points are (8,8) or (-8,-8)?
Why not other pairs (4,4), (-4,-4)?
Hope the image helps
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Re: A square with an area equal to 256 has its center at the
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20 Feb 2020, 20:21
20 Feb 2020, 20:21
RSQUANT wrote:
mouda wrote:
luffy wrote:
Possible intersections points: (8,8) or (-8,-8)
So given x=8, y=8 and for function f(x=8) = c*8*8*8
c*8*8*8 = 8
=> c = 1/64
So given x=8, y=8 and for function f(x=8) = c*8*8*8
c*8*8*8 = 8
=> c = 1/64
how do you know that the possible intersections points are (8,8) or (-8,-8)?
Why not other pairs (4,4), (-4,-4)?
Hope the image helps
so it can be (-8,8) and (8,-8) too?
Re: A square with an area equal to 256 has its center at the
[#permalink]
07 Mar 2020, 15:39
07 Mar 2020, 15:39
@prototypevenom correct I used those coordinates and got the same answer
Re: A square with an area equal to 256 has its center at the
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20 Jul 2023, 10:34
20 Jul 2023, 10:34
Hello from the GRE Prep Club BumpBot!
Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
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Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
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