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A theater box office sold an average (arithmetic mean) of 65 tickets p
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01 Nov 2021, 06:47
01 Nov 2021, 06:47
Expert Reply
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Question Stats:
78% (01:39) correct
21% (02:45) wrong based on 14 sessions
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A theater box office sold an average (arithmetic mean) of 65 tickets per staff member to a particular movie. Among the daytime staff, the average number sold per member was 76, and among the evening staff, the average number sold was 60. If there are no other employees, what was the ratio of the number of daytime staff members to the number of evening staff members?
1:4
5:11
7:11
65:76
1:1
1:4
5:11
7:11
65:76
1:1
Re: A theater box office sold an average (arithmetic mean) of 65 tickets p
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01 Nov 2021, 19:36
01 Nov 2021, 19:36
1
Let's say,
Daytime staff \(= x\) people & evening staff \(= y\) people
Total avg \(= 65\) ; daytime staff avg \(= 76\) & evening staff avg \(= 60\)
\(76x + 60y = 65( x + y )\)
\(11x = 5y\)
\(\frac{x}{y} = \frac{5}{11}\)
Answer B
Daytime staff \(= x\) people & evening staff \(= y\) people
Total avg \(= 65\) ; daytime staff avg \(= 76\) & evening staff avg \(= 60\)
\(76x + 60y = 65( x + y )\)
\(11x = 5y\)
\(\frac{x}{y} = \frac{5}{11}\)
Answer B
Re: A theater box office sold an average (arithmetic mean) of 65 tickets p
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01 Nov 2021, 21:58
01 Nov 2021, 21:58
1
Quote:
A theater box office sold an average (arithmetic mean) of 65 tickets per staff member to a particular movie. Among the daytime staff, the average number sold per member was 76, and among the evening staff, the average number sold was 60. If there are no other employees, what was the ratio of the number of daytime staff members to the number of evening staff members?
Let number of daytime staff members be x and number of evening staff members be y
average number of tickets sold = 65
average number tickets sold among daytime staff = 76
Difference above the mean = 76 - 65 = 11
Total difference above the mean = 11x
average number tickets sold among evening staff = 60
Difference below the mean = 65 - 60 = 5
Total difference below the mean = 5y
Total difference above the mean = Total difference below the mean
11x = 5y
x/y = 5/11
B is correct
