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Re: ab<1 and ac<1 [#permalink]
1
Carcass wrote:
Dealin' with this problem is nasty.

Picking numbers could be cumbersome and at the same time you will have a lot of errors.

abc=1 and we do know that b is positive >1 and could be any number: integer or fraction

at the same time picking be you have to make consistent the inequalities above such as ac<1 and the others. mhhhhh too lengthy

working with the inequalities themselves, pairing all of them is lengthy as well

Maybe the best approach is using the positive and negative assessment

We do know that b is positive and at the same time abc=1 . To be ABC =1 and b positive, a and c must be balance b in order to have 1 in the end. a and c NOT necessarily must be negative but considering that the

ab<1

ac<1

cb<1

a and c must be negative

In quantity A 1/a+c we do have a negative fraction and b we do know is positive

A is negative
B is positive

B > A

The answer is B

Great explanation! Thank you :)
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