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AB and CD are chords of the circle, and E and F are the mid
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23 Mar 2019, 08:56
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Question Stats:
44% (02:04) correct
55% (02:21) wrong based on 36 sessions
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#GREpracticequestion AB and CD are chords of the circle.jpg [ 17.99 KiB | Viewed 5610 times ]
AB and CD are chords of the circle, and E and F are the midpoints of the chords, respectively. The line EF passes through the center O of the circle. If EF = 17, then what is radius of the circle?
Re: AB and CD are chords of the circle, and E and F are the mid
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11 Apr 2020, 11:01
Expert Reply
AE = BE = 5 CF = FD = 12 EF = 17 OE = x, Then OF = 17-x
OAE is a right angle triangle, Apply Pythagorean theorem, OA = √25+x2 = radius Similarly, OCF is a right angle triangle, Apply Pythagorean theorem, OC = √(17−x)2+144 = radius
Equating both equations as both are the radii, we get 25+x2=289+x2−34x+144 34x = 408 x = 12 = OE, then OF = 5 OA = OC = √25+144 = 13