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ab is different from zero
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27 Jan 2020, 15:17
27 Jan 2020, 15:17
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\(ab \neq 0\)
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
_________________
Quantity A |
Quantity B |
\(\frac{a+b+c}{5}\) |
\(\frac{1}{5ab} + \frac{c}{5}\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
_________________
GRE Instructor
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Re: ab is different from zero
[#permalink]
28 Jan 2020, 04:34
28 Jan 2020, 04:34
1
Carcass wrote:
\(ab \neq 0\)
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Quantity A |
Quantity B |
\(\frac{a+b+c}{5}\) |
\(\frac{1}{5ab} + \frac{c}{5}\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Quantity A: \((a+b+c)/5\)
Quantity B: \(1/5ab + c/5 = (1 + abc)/5ab\)
Since there is no restriction on the values of \(a, b, c,\) let us take some scenarios:
Let \(c = 0\): [Note: \(ab\) is not zero; \(c\) can be zero]
Quantity A: \((a+b)/5\)
Quantity B: \(1/5ab\)
If \(a = b\):
Quantity A: \(2a/5\)
Quantity B: \(1/5a^2\)
If \(a = 1\): Quantity A = 2/5 and Quantity B = 1/5
=> Quantity A is greater
If \(a = -1\): Quantity A = -2/5 and Quantity B = 1/5
=> Quantity B is greater
Thus, there is no relation
Answer D
_________________
Sujoy Kr Datta | GMAT Q51 | CAT 99.99 | Mentor & Coach
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Re: ab is different from zero
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17 May 2023, 08:57
17 May 2023, 08:57
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