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Re: ABC is an equilateral triangle. If m∠DAC = m∠DCA = 40°, cho [#permalink]
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void wrote:
why option d is wrong?
after calculation measure of angle BCD =100 and angle ADC=120


I think you'll find that ∠ADC=100° degrees (since ∠DCA = ∠CAD = 40°)
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Re: ABC is an equilateral triangle. If m∠DAC = m∠DCA = 40°, cho [#permalink]
you are right ...calcullation mistake on myside .
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Re: ABC is an equilateral triangle. If m∠DAC = m∠DCA = 40°, cho [#permalink]
can anyone tell me the geometrical property used for option B.

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Re: ABC is an equilateral triangle. If m∠DAC = m∠DCA = 40°, cho [#permalink]
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arjunbir wrote:
can anyone tell me the geometrical property used for option B.

Thanks
Kind Regards


arjunbir

Greater the interior angle, greater is the side opposite to it

In triangle ADC, AD is opposite to 40 degree whereas AC is opposite to 100 degrees.
Also, AC = AB = BC

So, AD < BC
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Re: ABC is an equilateral triangle. If m∠DAC = m∠DCA = 40°, cho [#permalink]
Expert Reply
KarunMendiratta wrote:
arjunbir wrote:
can anyone tell me the geometrical property used for option B.

Thanks
Kind Regards


arjunbir

Greater the interior angle, greater is the side opposite to it

In triangle ADC, AD is opposite to 40 degree whereas AC is opposite to 100 degrees.
Also, AC = AB = BC

So, AD < BC



Thank you Sir
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Re: ABC is an equilateral triangle. If mDAC = mDCA = 40°, cho [#permalink]
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Re: ABC is an equilateral triangle. If mDAC = mDCA = 40°, cho [#permalink]
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