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ABCD and PQRS are parallelograms, if AD < PS and AB > PQ.
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26 Apr 2023, 02:21
26 Apr 2023, 02:21
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55% (01:05) correct
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ABCD and PQRS are parallelograms, if AD < PS and AB > PQ.
Quantity A |
Quantity B |
Area of ABCD |
Area of PQRS |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
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Re: ABCD and PQRS are parallelograms, if AD < PS and AB > PQ.
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07 May 2023, 09:06
07 May 2023, 09:06
1
You just need to plug in the values , checking with the conditions .
Let say you have there AD = 3; PS = 4 . And , AB = 5 UNITS and PQ = 4 units. use Pythagoras theorem to find the height of the parallelogram as it gives the height as 4 units. So A -> 1/2 * 4 * 3 = 6 sq units
B-> 4 * 4 16 square units . Hence Quantity B is greater .
Let say you have there AD = 3; PS = 4 . And , AB = 5 UNITS and PQ = 4 units. use Pythagoras theorem to find the height of the parallelogram as it gives the height as 4 units. So A -> 1/2 * 4 * 3 = 6 sq units
B-> 4 * 4 16 square units . Hence Quantity B is greater .
Re: ABCD and PQRS are parallelograms, if AD < PS and AB > PQ.
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03 Oct 2023, 09:18
03 Oct 2023, 09:18
Mohammzk wrote:
You just need to plug in the values , checking with the conditions .
Let say you have there AD = 3; PS = 4 . And , AB = 5 UNITS and PQ = 4 units. use Pythagoras theorem to find the height of the parallelogram as it gives the height as 4 units. So A -> 1/2 * 4 * 3 = 6 sq units
B-> 4 * 4 16 square units . Hence Quantity B is greater .
Let say you have there AD = 3; PS = 4 . And , AB = 5 UNITS and PQ = 4 units. use Pythagoras theorem to find the height of the parallelogram as it gives the height as 4 units. So A -> 1/2 * 4 * 3 = 6 sq units
B-> 4 * 4 16 square units . Hence Quantity B is greater .
I don't think you'll need Pythagoras theorem to get the height. Since, BR || AS, QP = RS is the height for ABCD. Also, how are you using the Pythagoras theorem? Because the base of the resulting right angle triangle needn't be = 3.
