AD is the diameter hence OD will be radius.

The hexagon is regular so all sides will be equal.

Triangle OBC will form an equilateral triangle.

OB = OC = BC = radius

Qt A

Radius OD = BC = EF = side of hexagon

Qt B

The length of arc \(\widehat{FE}\)

This can be calculated as = \(\frac{angle EOF}{360} * 2 * pi * radius\)
= \(\frac{60}{360} * 2 * pi * EF\)
= \(\frac{pi}{3} * EF\)
= 1.046 * EF

So Qt B > Qt A

Answer B
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We are told that hexagonal is inscribed inside the circle, the basic property of hexagonal states its consists 6 equilateral triangle.


Hence all side of the given triangle are equal.

But,
radius OD is straight line segment and FE is curve path,


Hence, FE is greater.
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pretend that the diameter of the circle = 10 thus the radius (QA) equals 5
The length of an arc = X/360 * 2*Pi*R (where x is the measure of the angle in question)
if the shape is a regular hexagon then each the internal angles are 720 degree ((6-2) * 180)
720 / 6 = 120
120 / 360 * 2 * pi * 5 (the radius we established earlier) = 3.3333333 * pi > 5