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Re: ABCDEF is a regular hexagon inscribed in circle O [#permalink]
pretend that the diameter of the circle = 10 thus the radius (QA) equals 5
The length of an arc = X/360 * 2*Pi*R (where x is the measure of the angle in question)
if the shape is a regular hexagon then each the internal angles are 720 degree ((6-2) * 180)
720 / 6 = 120
120 / 360 * 2 * pi * 5 (the radius we established earlier) = 3.3333333 * pi > 5
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Re: ABCDEF is a regular hexagon inscribed in circle O [#permalink]
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