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ABCG and CDEF are squares with the same area that touch at p
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25 Nov 2020, 03:19
25 Nov 2020, 03:19
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Question Stats:
72% (01:26) correct
27% (01:32) wrong based on 112 sessions
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ABCG and CDEF are squares with the same area that touch at point C. ∠BCD is a right angle.
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Quantity A |
Quantity B |
3 times the length of AB |
The length of AE |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Re: ABCG and CDEF are squares with the same area that touch at p
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23 Dec 2020, 03:16
23 Dec 2020, 03:16
2
If the area of the squares is the same, they must have the same lenght.
Choice A is 3 times AB.
Choice B can be found by tracing a triangle from A to E. Finding the hypothenus of one side AB and another side 2AB. Thus its \sqrt{5}*AB which is less than 3AB
Choice A is 3 times AB.
Choice B can be found by tracing a triangle from A to E. Finding the hypothenus of one side AB and another side 2AB. Thus its \sqrt{5}*AB which is less than 3AB
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ABCG and CDEF are squares with the same area that touch at p
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03 Jun 2021, 04:52
03 Jun 2021, 04:52
salvador1 wrote:
If the area of the squares is the same, they must have the same lenght.
Choice A is 3 times AB.
Choice B can be found by tracing a triangle from A to E. Finding the hypothenus of one side AB and another side 2AB. Thus its \sqrt{5}*AB which is less than 3AB
Choice A is 3 times AB.
Choice B can be found by tracing a triangle from A to E. Finding the hypothenus of one side AB and another side 2AB. Thus its \sqrt{5}*AB which is less than 3AB
I did not understand sir, can you please elaborate?
Carcass sir, please provide official solution, i stuck
