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AC and DE are both diameters of the circle shown below. If the area of
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05 Mar 2021, 06:30
05 Mar 2021, 06:30
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AC and DE are both diameters of the circle shown below. If the area of the circle is 180 \(units^2\), what is the total area of the shaded sectors?
A. 34 \(units^2\)
B. 36 \(units^2\)
C. 38 \(units^2\)
D. 40 \(units^2\)
E. 42 \(units^2\)
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Re: AC and DE are both diameters of the circle shown below. If the area of
[#permalink]
05 Mar 2021, 08:42
05 Mar 2021, 08:42
1
GeminiHeat wrote:
Attachment:
6.jpg
AC and DE are both diameters of the circle shown below. If the area of the circle is 180 \(units^2\), what is the total area of the shaded sectors?
A. 34 \(units^2\)
B. 36 \(units^2\)
C. 38 \(units^2\)
D. 40 \(units^2\)
E. 42 \(units^2\)
Angle ABD = Angle CBE = 40 .............. [Vertically opposite angles are equal]
More the Angle, more is the Area.
Which means they are Directly proportional and their ratios must be equal
So, \(\frac{360}{180} = \frac{(40+40)}{Area}\)
\(Area = \frac{(80)(180)}{360} = 40\)
Hence, option D
gmatclubot
Re: AC and DE are both diameters of the circle shown below. If the area of [#permalink]
05 Mar 2021, 08:42
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