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GRE Prep Club Team Member
Joined: 20 Feb 2017
Posts: 2506
Given Kudos: 1055
GPA: 3.39
After running a series of television advertisements, a leading beverag
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22 Jan 2021, 08:34
22 Jan 2021, 08:34
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Question Stats:
60% (01:10) correct
40% (00:44) wrong based on 5 sessions
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After running a series of television advertisements, a leading beverage producer saw its sales increase by 25% to $1 million dollars per month. Prior to the advertising campaign, about how many dollars in sales did the company average per day?
A) $1.25 million
B) $800,000
C) $750,000
D) $27,000
E) $10,000
A) $1.25 million
B) $800,000
C) $750,000
D) $27,000
E) $10,000
After running a series of television advertisements, a leading beverag
[#permalink]
22 Jan 2021, 09:25
22 Jan 2021, 09:25
1
Sales increment by 25 % , so multiplier = 1.25
New sales = $1 mn
Prior to advertising, sales = \(\frac{1}{1.25}\) = \(\frac{4}{5}\)
= $0.80 mn = $800,000 / month
The question is asking for sales per day = \(\frac{800,000}{30}\)
= 27000
Answer D
Hint : Always convert percentage values in multipliers.
New sales = $1 mn
Prior to advertising, sales = \(\frac{1}{1.25}\) = \(\frac{4}{5}\)
= $0.80 mn = $800,000 / month
The question is asking for sales per day = \(\frac{800,000}{30}\)
= 27000
Answer D
Hint : Always convert percentage values in multipliers.
GRE Prep Club Team Member
Joined: 20 Feb 2017
Posts: 2506
Given Kudos: 1055
GPA: 3.39
Re: After running a series of television advertisements, a leading beverag
[#permalink]
22 Jan 2021, 09:29
22 Jan 2021, 09:29
1
1
Expert Reply
rx10 wrote:
Sales increment by 25 % , so multiplier = 1.25
New sales = $1 mn
Prior to advertising, sales = \(\frac{1}{1.25}\) = \(\frac{4}{5}\)
= $0.80 mn = $800,000
Answer B
Hint : Always convert percentage values in multipliers.
New sales = $1 mn
Prior to advertising, sales = \(\frac{1}{1.25}\) = \(\frac{4}{5}\)
= $0.80 mn = $800,000
Answer B
Hint : Always convert percentage values in multipliers.
You might need to read the question again!
Thank you
