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Re: Alejandro has a six-sided die with faces numbered 1 through [#permalink]
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Carcass wrote:

The last collection of questions for the GRE Quant - 2019




Alejandro has a six-sided die with faces numbered 1 through 6. He rolls the die twice.

Quantity A
Quantity B
The probability that both rolls are even
The probability that neither roll is a multiple of 3



A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.


Without getting into probability, the answer will be the choice that has more ways..
The probability that both rolls are even - so there are 3 ways in which it can be even .. the ways = 3*3=9
The probability that neither roll is a multiple of 3 - so the wording has changed from both to neither. thus there are 4 ways of not having a multiple of 3, => 4*4=16

Thus 16>9 or B>A
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Re: Alejandro has a six-sided die with faces numbered 1 through [#permalink]
The probability that the two rolls are even is \(\frac{3}{6} * \frac{3}{6} which is \frac{1}{4}\)
possible even nos are :2, 4 and 6.
The probability that neither roll is a multiple of 3 becomes
\(\frac{4}{6} * \frac{4}{6}\) which is \(\frac{4}{9}\)
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Re: Alejandro has a six-sided die with faces numbered 1 through [#permalink]
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Re: Alejandro has a six-sided die with faces numbered 1 through [#permalink]
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