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All the students in the Computer Science club went to at least one
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Updated on: 10 Mar 2022, 22:31
Updated on: 10 Mar 2022, 22:31
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15% (01:50) correct
84% (01:51) wrong based on 65 sessions
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All the students in the Computer Science club went to at least one of the two hackathons sponsored by the club. 75 percent of the students went only to only one of the hackathons and 9 students went to both of the hackathons.
A) Quantity A is greater
B) Quantity B is greater
C) The two quantities are equal
D) The relationship cannot be determined from the information given
Quantity A |
Quantity B |
The number of students who attended only one hackathon |
18 |
A) Quantity A is greater
B) Quantity B is greater
C) The two quantities are equal
D) The relationship cannot be determined from the information given
Originally posted by bunterocks on 19 Oct 2020, 03:24.
Last edited by Carcass on 10 Mar 2022, 22:31, edited 1 time in total.
Last edited by Carcass on 10 Mar 2022, 22:31, edited 1 time in total.
Fixed OAs
Re: All the students in the Computer Science club went to at least one
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21 Oct 2020, 09:44
21 Oct 2020, 09:44
3
Call the total number of students T. Call x the number of students who take one and only one of the hackatons. Since the number of students who did not participate in both hackatons is 0, we have T=x+9.
x/(x+9)=0.75. Solving for x: x=27. The answer is A.
x/(x+9)=0.75. Solving for x: x=27. The answer is A.
Re: All the students in the Computer Science club went to at least one
[#permalink]
06 Aug 2021, 21:57
06 Aug 2021, 21:57
1
All students in computer science club went to atleast one of the 2 hackathons --> deduction neither/none is zero.
Let x be the total students in club.
75 percent of students went to only one of the hackathons means --> only H1 +only H2 is 0.75x
So Union/Atleast1 = 0.75x+9
Total students = Atleast1 + neither
Deduction Atleast1 is x
Hence x is 36.Therefore 0.75x is 27, now qty A the number of students who attended only one hackathon ony H1 or Only H2 two cases we can have 9 only H1 or 18 only H2 hence D.
Posted from my mobile device
Let x be the total students in club.
75 percent of students went to only one of the hackathons means --> only H1 +only H2 is 0.75x
So Union/Atleast1 = 0.75x+9
Total students = Atleast1 + neither
Deduction Atleast1 is x
Hence x is 36.Therefore 0.75x is 27, now qty A the number of students who attended only one hackathon ony H1 or Only H2 two cases we can have 9 only H1 or 18 only H2 hence D.
Posted from my mobile device
