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Re: An apartment building has apartments numbered 2 through 85 [#permalink]
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Without doubt D
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Re: An apartment building has apartments numbered 2 through 85 [#permalink]
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Re: An apartment building has apartments numbered 2 through 85 [#permalink]
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Carcass wrote:
An apartment building has apartments numbered 2 through 85, consecutively.

Quantity A
Quantity B
The probability that the apartment number of a randomly selected tenant contains a 4
\(\frac{3}{14}\)


Quantity A is greater.
Quantity B is greater.
The two quantities are equal.
The relationship cannot be determined from the information given.


Consider these two cases.....

Case i: Each apartment has one occupant, EXCEPT for apartment #4, which has 1 BILLION occupants.
In other words, 1,000,000,083 people live in the apartment, 1,000,000,000 of whom live in apartment #4.
So if we randomly select someone from the apartment, it's very very very very very likely that that person lives in apartment #4.
So, in this case P(apartment number of a randomly selected tenant contains a 4) = a number very close to 1.
In this case, QUANTITY A IS GREATER

Case ii: Each apartment has one occupant, EXCEPT for apartment #5, which has 1 BILLION occupants.
In other words, 1,000,000,083 people live in the apartment, 1,000,000,000 of whom live in apartment #5.
So if we randomly select someone from the apartment, it's very very very very very likely that that person lives in apartment #5.
So, in this case P(apartment number of a randomly selected tenant contains a 4) = a number very close to 0.
In this case, QUANTITY B IS GREATER

Answer: D
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Re: An apartment building has apartments numbered 2 through 85 [#permalink]
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such questions are discriminatory in nature.
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Re: An apartment building has apartments numbered 2 through 85 [#permalink]
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The answer is C

The total number of apartment numbers containing 4 is 18. Hence 18/(85-2+1)=18/84 = 3/14. Hence C.
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