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An elevator in an 11-story office building travels at the rate of one
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19 Aug 2021, 05:27
19 Aug 2021, 05:27
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An elevator in an 11-story office building travels at the rate of one floor per 15 seconds, which allows time for picking up and discharging passengers. At the main floor and at the top floor, the operator stops for 60 seconds.
A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
Quantity A |
Quantity B |
Number of complete trips an operator can make in 7 hours |
56 |
A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
Retired Moderator
Joined: 19 Nov 2020
Posts: 326
Given Kudos: 64
GRE 1: Q160 V152
An elevator in an 11-story office building travels at the rate of one
[#permalink]
19 Aug 2021, 08:55
19 Aug 2021, 08:55
1
rate of elevator, v=\(\frac{1}{15}\) floor per second
time spent for two stops in one complete trip, T =120 seconds
time spent for traveling the distance (d) of 11 floors at the given rate (v) is t=\(d/v\)=\(\frac{11}{(1/15)}\)
time spent for one complete trip = t+T = \(120+15*11=285\) seconds
In 7 hours the number of complete trips = \(\frac{7*60*60}{285}=88\)
IMO, answer is A
time spent for two stops in one complete trip, T =120 seconds
time spent for traveling the distance (d) of 11 floors at the given rate (v) is t=\(d/v\)=\(\frac{11}{(1/15)}\)
time spent for one complete trip = t+T = \(120+15*11=285\) seconds
In 7 hours the number of complete trips = \(\frac{7*60*60}{285}=88\)
IMO, answer is A
KarunMendiratta wrote:
An elevator in an 11-story office building travels at the rate of one floor per 15 seconds, which allows time for picking up and discharging passengers. At the main floor and at the top floor, the operator stops for 60 seconds.
A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
Quantity A |
Quantity B |
Number of complete trips an operator can make in 7 hours |
56 |
A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
Retired Moderator
Joined: 16 Apr 2020
Status:Founder & Quant Trainer
Affiliations: Prepster Education
Posts: 1546
Given Kudos: 172
Location: India
WE:Education (Education)
Re: An elevator in an 11-story office building travels at the rate of one
[#permalink]
21 Aug 2021, 23:06
21 Aug 2021, 23:06
3
Explanation:
Since we start from Main floor and go up 10 floors, time taken = 60 + 15(10) = 60 + 150 = 210 seconds
Now, we wait at 11th floor and then go down 10 floors, time taken = 60 + 15(10) = 60 + 150 = 210 seconds
Total time for 1 round trip = 210 + 210 = 420 seconds
Total trips in 7 hrs = \(\frac{7(60)(60)}{420}\) = 60
Col. A: 60
Col. B: 56
Hence, option B
Since we start from Main floor and go up 10 floors, time taken = 60 + 15(10) = 60 + 150 = 210 seconds
Now, we wait at 11th floor and then go down 10 floors, time taken = 60 + 15(10) = 60 + 150 = 210 seconds
Total time for 1 round trip = 210 + 210 = 420 seconds
Total trips in 7 hrs = \(\frac{7(60)(60)}{420}\) = 60
Col. A: 60
Col. B: 56
Hence, option B
