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An equal number of juniors and seniors are trying out for
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05 Oct 2017, 20:38
05 Oct 2017, 20:38
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Question Stats:
59% (01:40) correct
40% (03:27) wrong based on 42 sessions
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An equal number of juniors and seniors are trying out for six spots on the university debating team. If the team must consist of at least four seniors, then how many different possible debating teams can result if five juniors try out?
(A) 50
(B) 55
(C) 75
(D) 100
(E) 250
Kudos for correct solution.
(A) 50
(B) 55
(C) 75
(D) 100
(E) 250
Kudos for correct solution.
Re: An equal number of juniors and seniors are trying out for
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05 Oct 2017, 21:36
05 Oct 2017, 21:36
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Bunuel wrote:
An equal number of juniors and seniors are trying out for six spots on the university debating team. If the team must consist of at least four seniors, then how many different possible debating teams can result if five juniors try out?
(A) 50
(B) 55
(C) 75
(D) 100
(E) 250
Kudos for correct solution.
(A) 50
(B) 55
(C) 75
(D) 100
(E) 250
Kudos for correct solution.
Here it is given as five juniors try out i.e we have 5 juniors and 5 seniors since equal number try out for the six spots
Now we can have two combination
first one - 4 seniors and 2 juniors = 5C4 * 5C2 =50 (We have to keep minimum nos of seniors to 4 as the statement says atleast 4 numbers of seniors are in the team)
Second one- 5 seniors and 1 juniors = 5C5 * 5C1 = 5
Therefore total possible teams = 50 + 5 =55
Re: An equal number of juniors and seniors are trying out for
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10 Jan 2019, 23:07
10 Jan 2019, 23:07
Expert Reply
For anyone who gets stumped by which way to use combinatorics, lets think about this.
First,
They say that there are equal numbers of juniors and seniors, and there are 5 juniors, which means there are 5 seniors and a total of 10 players
Now, lets find the total number of all 6 team combinations out of 10 players, which is 10c6= 210, so it cant be greater than this number,
which means we eliminate E
Its said that there are at least 4 seniors that must be on the team, which means that there are 4 out of 5 seniors that have to be picked, leaving only 2 out of 5 Juniors that can be picked after.
picking 4 out of 5 seniors is 5c4,
picking 2 out of 5 juniors is 5c2
thus 5c4*5c2= 5*10= 50
but what if 5 out of 5 seniors get picked? then 5c5=1
leaving only 1 out of 5 juniors to be picked, 5c1=5
Thus 5c5*5c1= 1*5=5
add all the possible combinations to get 50=5=55
We choose B
First,
They say that there are equal numbers of juniors and seniors, and there are 5 juniors, which means there are 5 seniors and a total of 10 players
Now, lets find the total number of all 6 team combinations out of 10 players, which is 10c6= 210, so it cant be greater than this number,
which means we eliminate E
Its said that there are at least 4 seniors that must be on the team, which means that there are 4 out of 5 seniors that have to be picked, leaving only 2 out of 5 Juniors that can be picked after.
picking 4 out of 5 seniors is 5c4,
picking 2 out of 5 juniors is 5c2
thus 5c4*5c2= 5*10= 50
but what if 5 out of 5 seniors get picked? then 5c5=1
leaving only 1 out of 5 juniors to be picked, 5c1=5
Thus 5c5*5c1= 1*5=5
add all the possible combinations to get 50=5=55
We choose B
