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Andy drove from Townville to Villageton at an average speed of 40 mile
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01 Dec 2022, 06:31
01 Dec 2022, 06:31
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Question Stats:
57% (01:17) correct
42% (00:50) wrong based on 52 sessions
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Andy drove from Townville to Villageton at an average speed of 40 miles per hour. He then drove from Villageton to Townville at an average speed of 60 miles per hour.
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
50 |
The average speed of Andy's entire trip in miles per hour. |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
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Re: Andy drove from Townville to Villageton at an average speed of 40 mile
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02 Dec 2022, 09:28
02 Dec 2022, 09:28
1
Expert Reply
Time= distance/speed
d/40+d/60=5d/120
average speed is 2d/5d/120 =48
A is the answer
d/40+d/60=5d/120
average speed is 2d/5d/120 =48
A is the answer
Re: Andy drove from Townville to Villageton at an average speed of 40 mile
[#permalink]
02 Dec 2022, 09:31
02 Dec 2022, 09:31
1
Expert Reply
second approach is to use weighted avergae
sum up the two speeds 60+40=100/2=50
However the first stretch is faster than the second one and it pulls down the overall speed to less than 50
a is the answer
sum up the two speeds 60+40=100/2=50
However the first stretch is faster than the second one and it pulls down the overall speed to less than 50
a is the answer
