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Re: As a bicycle salesperson [#permalink]
Since in second week, his earning is more than double than 1st week, therefore y>x
and then if we go by logic, if Norman sells less than 3 bikes in 1st week, his salary will be 20$, so in order to make more than double money in 2nd week, he needs to sell more than 3 bikes, i.e. y>3
Since no. of bikes he can sell in 2nd week is unlimited, no. of bikes he can sell in 1st week is also unlimited, x>5 making option 1 wrong.
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Re: As a bicycle salesperson [#permalink]
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Re: As a bicycle salesperson [#permalink]
2
This problem seems tricky but doesn't need a lot of calculations to begin with,
let's check out the answer choices,
A. x < 5 :: there is no limit to bicycles sold in the second week so x need not be less than 5 , note the question asks for statements must be, x need not be < 5

B. y > x ::obviously, if you're making more salary then more bikes has to sold because fixed salary is 20

C. y > 3 :: this is where we might need some calculation, Total Salary would be 20 + 3(6) = 38, now assuming he didn't sell any bikes in week1 his salary still would be 20 and 38 is < than twice week 1 so C has to be true.
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Re: As a bicycle salesperson [#permalink]
1
For the first week
20+ 6(3) +12(3)+18 (X-6) = A

18X - 34 = A

So 2nd week will be

18X - 34 = 2A
Combining the two gives
18X - 9Y = 17
From this we can see that
Y is greater than X
Y is greater than 3
And X must be greater than 5.
Answer B and C.
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Re: As a bicycle salesperson [#permalink]
Hello from the GRE Prep Club BumpBot!

Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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