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GRE Prep Club Team Member
Joined: 20 Feb 2017
Posts: 2506
Given Kudos: 1055
GPA: 3.39
As shown in the figure above, a thin conveyor belt 15 feet long is dra
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24 Sep 2022, 06:36
24 Sep 2022, 06:36
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Expert Reply
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Question Stats:
100% (01:55) correct
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As shown in the figure above, a thin conveyor belt 15 feet long is drawn tightly around two circular wheels each 1 foot in diameter. What is the distance, in feet, between the centers of the two wheels?
A. \(\frac{15-\pi}{2}\)
B. \(\frac{5\pi}{4}\)
C. \(15-2\pi\)
D. \(15-\pi\)
E. \(2\pi\)
Re: As shown in the figure above, a thin conveyor belt 15 feet long is dra
[#permalink]
28 Sep 2022, 07:00
28 Sep 2022, 07:00
Expert Reply
The length of the belt = (semi perimeter of circle1) + 2* distance between the centres of the circles + (semi perimeter of circle2)
let's say the distance between the centres of the circles = d.
since both the circles have diameter = 1 ft ,therefore their radius = .5ft
therefore semiperimeter of each of the circles = (1/2) * 2* pi * r
= pi* .5
so,
15 = (pi* .5) + 2d + (pi*.5)
15 = pi + 2d
therefore d = (15-pi)/2
Hence option A
let's say the distance between the centres of the circles = d.
since both the circles have diameter = 1 ft ,therefore their radius = .5ft
therefore semiperimeter of each of the circles = (1/2) * 2* pi * r
= pi* .5
so,
15 = (pi* .5) + 2d + (pi*.5)
15 = pi + 2d
therefore d = (15-pi)/2
Hence option A
gmatclubot
Re: As shown in the figure above, a thin conveyor belt 15 feet long is dra [#permalink]
28 Sep 2022, 07:00
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