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As shown in the figure, the circle with center (6,4)
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06 Sep 2023, 03:27
06 Sep 2023, 03:27
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Question Stats:
75% (01:30) correct
25% (02:08) wrong based on 4 sessions
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As shown in the figure, the circle with center (6,4) intersects the x-axis at (2,0) and (10,0). Which of the following is the equation of the circle?
A. \((x – 4)^2 + (y – 6)^2 = 32\)
B. \((x – 6)^2 + (y – 4)^2 = \sqrt{32}
\)
C. \((x – 4)^2 + (y – 6)^2 = 16\)
D. \((x – 6)^2 + (y – 4)^2 = 32\)
E. \((x + 6)^2 + (y + 4)^2 = 32\)
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Re: As shown in the figure, the circle with center (6,4)
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08 Sep 2023, 11:42
08 Sep 2023, 11:42
1
The equation for a circle is (x-h)^2 + (y-k)^2 = r^2. h and k are the x and y coordinates of the center. The radius is the distance between the center and (2,0). This is 4 root 2.
The equation is (x-6)^2 + (y-4)^2 = (4 root 2)^2. 4 root 2 squared is 32. D is correct.
The equation is (x-6)^2 + (y-4)^2 = (4 root 2)^2. 4 root 2 squared is 32. D is correct.
gmatclubot
Re: As shown in the figure, the circle with center (6,4) [#permalink]
08 Sep 2023, 11:42
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