MinakshiS wrote:
Ks1859 wrote:
Solution:
p<q<100 i.e. The time taken by A to complete a work>the time taken by B to complete a work
Thus in order to do the consignment, A will take more time than B
Qty A>Qty B
IMO A
Hope this helps!
.......
PS - This does not hold true is you assume p =98 and q=99. Because there is no definitive relationship between p and q, the answer can't be determined. The right answer IMO should be D
Hi There!
When you divide 1000 by 98 or by 99 you
DO NOT GET THE SAME QUOTIENT. Let me try helping you with this.
**Use calculator for precise values**.
\(\frac{1000}{99}=10.1010101010101--Machine B\)
\(\frac{1000}{98}=10.20408163265306--Machine A\)
So the above values are simply the time required to complete the work in days and the decimal value is the extra part of another day after the 10 days to finish the 1000 unit.
Because if we only consider 11 days then Machine A which does 98 units of work in 1 day will do 1078 units we do not need those extra 78 units, as the question only asks for 1000 units make sure you only find the value corresponding to 1000. Do no round off. Similarly, for Machine B.
Now, you tell me isn't 10.20>10.10. Just because these are some decimal values, we can't ignore them.
The Correct Answer is A because of the above reason. As it takes A more time as it does less units of work per day than B does.
Ask for further assistance.
P.S:. Welcome to the GRE Club
Hope this helps!