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At a recent company meeting, there were 14 project managers and 10 eng
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15 Sep 2021, 09:34
15 Sep 2021, 09:34
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At a recent company meeting, there were 14 project managers and 10 engineers in attendance, with an overall average age of 31. If the average age of the project managers was 36, what was the average age of the engineers?
A. 24
B. 25
C. 26
D. 28
E. 30
A. 24
B. 25
C. 26
D. 28
E. 30
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Re: At a recent company meeting, there were 14 project managers and 10 eng
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15 Sep 2021, 10:01
15 Sep 2021, 10:01
1
Carcass wrote:
At a recent company meeting, there were 14 project managers and 10 engineers in attendance, with an overall average age of 31. If the average age of the project managers was 36, what was the average age of the engineers?
A. 24
B. 25
C. 26
D. 28
E. 30
A. 24
B. 25
C. 26
D. 28
E. 30
This is a nice weighted averages question.
Weighted average of groups combined = (group A proportion)(group A average) + (group B proportion)(group B average) + (group C proportion)(group C average) + ...
So: average age of COMBINED workers = (proportion of project managers)(average age of project managers) + (proportion of engineers)(average age of engineers)
We have a total of 24 workers (14 project managers + 10 engineers = 24 workers)
So, the proportion of project managers = 14/24 = 7/12
The proportion of engineers = 10/24 = 5/12
Let E = average age of engineers
Now, plug everything into the formula to get:
31 = (7/12)(36) + (5/12)(E)
Simplify: 31 = 21 + 5E/12
Subtract 21 from both sides: 10 = 5E/12
Multiply both sides by 12 to get: 120 = 5E
Solve: E = 24
Answer: A
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Re: At a recent company meeting, there were 14 project managers and 10 eng [#permalink]
15 Sep 2021, 10:01
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