Carcass wrote:
At a restaurant, all tips are added together to be split among the employees at the end of a shift. The 4 waiters combined get \frac{2}{3} of the money, the manager receives \frac{1}{4} and the busboy receives the remainder. If 1 waiter and the busboy together receive $30, how much money was earned in tips for the entire shift?
A. $90
B. $96
C. $108
D. $120
E. $180
Kudos for the right answer and explanation[/m]
Here,
Let the total Tips = X
Now, 4 waiters combined get =
\frac{2X}{3} and
1 waiter receives = \frac{2X}{12} Manager receives =
\frac{X}{4} the busboy receives = X - (
\frac{2X}{3} + \frac{X}{4}) =
\frac{X}{12} Since,
1 waiter and the busboy together receive $30
therefore,
\frac{2X}{12} + \frac{X}{12} = $30
or X = $120