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At her current job, Mary gets a 1.5% raise twice per year. W
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Updated on: 01 Nov 2024, 10:04
Updated on: 01 Nov 2024, 10:04
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At her current job, Mary gets a 1.5% raise twice per year. Which of the following choices represents Mary’s current income y years after starting the job at a starting salary of s?
(A) \(s(1.5)^{2y}\)
(B) \(s(0.015)^{2y}\)
(C) \(s(1.015)^{2y}\)
(D) \(s(1.5)^{\frac{y}{2}}\)
(E) \(s(1.015)^{\frac{y}{2}}\)
(A) \(s(1.5)^{2y}\)
(B) \(s(0.015)^{2y}\)
(C) \(s(1.015)^{2y}\)
(D) \(s(1.5)^{\frac{y}{2}}\)
(E) \(s(1.015)^{\frac{y}{2}}\)
Re: At her current job, Mary gets a 1.5% raise twice per year. W
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07 Jan 2019, 15:12
07 Jan 2019, 15:12
sandy wrote:
At her current job, Mary gets a 1.5% raise twice per year. Which of the following choices represents Mary’s current income y years after starting the job at a starting salary of s?
(A) \(s(1.5)^{2y}\)
(B) \(s(0.015)^{2y}\)
(C) \(s(1.015)^{2y}\)
(D) \(s(1.5)\frac{y}{2}\)
(E) \(s(1.015)\frac{y}{2}\)
(A) \(s(1.5)^{2y}\)
(B) \(s(0.015)^{2y}\)
(C) \(s(1.015)^{2y}\)
(D) \(s(1.5)\frac{y}{2}\)
(E) \(s(1.015)\frac{y}{2}\)
After y years income will be= \(s(1+0.015)^{2y}\)
=\(s(1.015)^{2y}\)
Ans C.
Re: At her current job, Mary gets a 1.5% raise twice per year. W
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01 Nov 2024, 10:04
01 Nov 2024, 10:04
Expert Reply
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